Hi ... I have the following source code .... which I am having problems
with.
Basically, I am trying to point to an object using pointers and access its
member variables via the pointer ... no luck ...  I hope you can help shed
light on this problem ...

Cheers,
Joe.

-----------------------
#include <stdio.h>

class TItem {
   public :
      double amount ;
      int position ;

class TTrolley {
   public :
      TItem cereal ;
      void Purchase ( TItem *item) ;

void TTrolley::Purchase ( TItem *item) {
   item = &cereal ;

main () {

  TItem *item_ptr = new TItem ;
  TTrolley Cart ;

  Cart.cereal.amount = 24.0 ;  // initialise amount
  Cart.cereal.position = 6 ;   // initialise pos

  Cart.Purchase(item_ptr) ;

  //
  //   I GET GARBAGE VALUES HERE WHEN I PRINT THEM TO SCREEN ..
  //   Basically, all I want to be able to do is access the member
  //   variables of an object that a pointer is pointed to ...
  //   It is obviusly NOT working here ...
  //

  printf ("\n item_ptr->amount = %2.1f", item_ptr->amount);
  printf ("\n item_ptr->position = %d", item_ptr->position);

// PS: Please send a copy of your reply to jredi...@hotmail.com
//  Thank you ..

Shouldn't that be
  *item = &cereal;

.  Ed

int main() {

This passes a pointer to a TItem.

The parameter item is a *copy* of item_ptr. Assigning item a different
address doesn't change item_ptr; only the copy is changed.

You basically have two choices:

1) Modify the object item_ptr and item refer to:

void TTrolley::Purchase ( TItem *item) {
   *item = cereal ;

2) Pass item_ptr by reference so that the assignment inside Purchase()
propagates to its caller:

void TTrolley::Purchase ( TItem * &item) {
   item = &cereal ;

Note that this "solution" causes the object dynamically allocated on the
first line of main() to be leaked.

No.

Thanks Thomas .... it worked !!

Joe.

You are welcome.

Would you please not quote entire posts you are following up to, like

[deleted a lot of stuff]

Thanks!

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